I variant
- Solve the problem.
Two boats left two moorings simultaneously towards each other. The speed of the first boat is 6 km/h and it traveled 18 km before the meeting. The speed of the second boat is 9 km. What distance did the second boat travel before the meeting?
- Perform the calculations in column.
5786 + 3427
4325 . 53
8034 – 5896
41741 : 7
- Calculate the value of the expression.
578 + (801 – 316) . 29
- Solve the equations.
х – 7653 = 2489
х : 6 = 9
- Solve the problem.
A rectangle is 6 cm long and 2 cm wide. Find the perimeter and the area.
II variant
- Solve the problem.
Two motor ships departed from two wharves at the same time to meet each other. The speed of the first one was 24 km/h and it had passed 96 km before the meeting. The second ship had travelled 120 km before the meeting. What is its speed?
- Perform a column calculation.
6984 + 4375
5672 . 86
7065 – 4387
47576 : 8
3.Calculate the value of the expression.
449 + 26 . (7854 – 4386)
- Solve the equations.
8045 – х = 6236
х : 4 = 8
- Solve the problem.
The length of the rectangle is 5 cm and the width is 2 cm less. Find the perimeter and the area.